Requested by User:Legion350 here
So, I'll assume it's as tall as a cumulonimbus, 8000 to 11,000 meters, and, it covers a town a mile wide, 1609.344 meters.
put those together and it's 12874752 and 17702784 meters cubed
a cumulonimbus is 1-3 grams per meter, I'll assume 1 here, so, 12874752 and 17702784 grams, 12874.752 and 17702.784 Kilograms
Condensation is determined using 2264705 j/kg, so, put those together and it's
Low End: 29157515228.2 Joules, 6.96881339105 Tons, Large Building level, probably +
High End: 40091583438.7 Joules, 9.5821184127 Tons, Large Building level+
Edit[]
He apparently meant a mile in diameter, not area.
In that case, it's pi times 8,000 and 11,000 times 804.672 squared, 16273375240.632 and 22375890955.870 meters cubed
Times 1 and divided by 1,000 is 16273375.2406329 and 22375890.9558703 Kilograms
Times 2264705 j/kg is....
Low End: 36854394274337 joules, 8.80841163344591 Kilotons, Town level
High End: 50674792127214.2477615 Joules, 12.1115659959881 Kilotons, Town level
New method[]
So, using this I could look into how much it would take to get so much air to freezing temperatures.
The density of air is 1.225 kg/m^3, so that times 16273375240.632 and 22375890955.870 is 19934884669.7742 and 27410466420.94075 Kilograms
The baseline temperature of a bizzard is -12 Degrees Celsius, with average temperatures being 16 C, making the temperature change 28.
Now, putting all of this in the Calcuator gets us
Low End: 564,874,892,002,722 Joules, 135.008339388795 Kilotons, Large Town level
High End: 776,702,976,503,777 Joules, 185.636466659602 Kilotons, Large Town level