Board Thread:Wiki Management/@comment-27123758-20180715015347/@comment-28644276-20190217053907

v = the square root of ((2*m*g)/(ρ*A*C))

P = density of air = 0.7048 at 3500 meters, which is more or less the height she fell from. C = drag coefficient = 0.6 is a rough estimate for the human form. Going with a 0.5 since she's a 4 years old. A = Projected area = 0.5, same as above. Going with 0.4 then. g = gravity constant = 9.8 m = mass = 15 kg, average for a four years old. V = Terminal velocity, what we need to find

V= square root of 2 * 15 * 9.8 / 0.7048 * 0.5 * 0.4

V = 294/0,14096

V = 1965, 24064171123

Square root of it gives me:

V = 44,331 m/s

Which shows how much physics actually slows stuff down when it starts falling as it comes nowhere close to the 183.92824687904795 m/s that we get if there's no Air Friction (granted her size and weight and drag coefficient also changed so). Oof.

Anyways, now for KE:

KE = 0.5 * mv²

KE = 0.5 * 15 * 44,331²

KE = 0.5 * 15 * 1965,2

KE = 14 739 J

Which is like less than 300 joules away from baseline Wall Level. Oof.

...I was expecting higher but given her actual age, the dramatic drop in weight from a 13 year old to a 4 year old and Air Resistance being a thing now to drop her velocity as well, it actually makes sense.