User blog:DMUA/Fox Dad: A furry pokes his wife, chaos ensues

Requested by User:Robot972 here



Earth is 611 pixels, while the first bolt is 9 pixels in radius, the second bolt is 6 pixels, and the third bolt is 2.5 pixels, a discrepancy of 0.0147299509, 0.00981996726, and 0.00409165302 pixels respectively.

Earth's Diameter is 12724 KM, so, they'd be 187.689034368, 125.126022827, and 52.1358428805 KM in radius, or, for our purposes, 187689.034368, 125126.022827 and 52135.8428805 meters

To find the energy of a lightning bolt, you need to find the density, which you find via the surface area of it's strike (in meters, of course)

So, the surface area of where a lightning bolt would strike is 3.14*r^2. In this case, 3.14*187689.034368^2, 3.14*125126.022827^2 and 3.14*52135.8428805^2, which would get 110613325173, 49161477787.9, and 8534978794.38 meters squared. Times 955*10^6 makes for 1.0563573e+20, 4.6949211e+19 and 8.1509047e+18.

Now at this point, I have no clue how the math works, so I'll copy off of copying

Multiplying everything by 10^9 gets 1.0563573e+29, 4.6949211e+28, and 8.1509047e+27

Energy = Power*Time, the timeframe for a lightning bolt is 0.000051 seconds. So, that makes the energy 5.3874222e+24, 2.3944098e+24 and 4.1569614e+23 for each bolt. Putting it together is...

8.1975281e+24 Joules, 1.95925624761 Petatons, Continent level