User blog:GreyFang82/The Carnival of Enigmatic Folk: Wall Busting

So in the story, the group fights a strongman who completely destroyed a brick wall and so such a feat must be calculated.

The Strongman is pretty tall, considerably above average so lets assume... 6' 5" (Yes I know that it is in heathen measurements) and the wall is taller than him. Let's assume the wall is 7 feet tall. So that's the height of the wall, know the width and length. Let's assume is as long as it is tall so 7 feet. The wall is only 1 block thick, according to this website the standard brick is is 3 and 5/8th of an inch in thickness.

Now converting those into normal human measurements that's 213.36 cm for length and height and 9.2075 cm in width. Using the volume formula of a which is w x l x h it should look like:

9.2075 x 213.36 x 213.36 = 419148.322992 cm^3

Now we plug in the values for frag and v.frag of concrete (Just to be on the safe side).

Conclusion
Low-Ball 419148.322992 x 6 = 2514889.93795 joules - Wall Level

High-Ball 419148.322992 x 20 = 8382966.45984 joules - Wall Level