Board Thread:General Discussion/@comment-31395794-20170505220933/@comment-31395794-20170618112350

Darkanine wrote: 1. Depends on the method of destruction. Does this mean to cause an explosion so massive it consumes the entire area or actually destroy the entire landmass of the continents?

If the former:

A rough diameter of the USA (East Coast to West Coast) is 4626.145 kilometers. We cut this in half to find the Radius.

4626.145 = 2313.0725 km

The formula for non-nuclear explosions is:

2313.0725 = Y^(1/3)*0.28

R = 2313.0725 km

Y = 563,759,199,696.200684 KT

Or 563 Teratons. Large Country level+

If the ladder:

The land area of mainland USA is 7,663,941.7 km^2 and has an average elevation of 0.76 km

Volume = Area * Elevation

7,663,941.7 * 0.76 = 5,824,595.692 km^3

5,824,595.692 * 1e+15 = 5.8245957e+21 cm^3

Assuming Fragmentation:

5.8245957e+21 * 8 = 4.6596766e+22 J

11 Teratons. Country level

2. The Gravitational Binding Energy of Mars is 1.144 Zettatons. Which is Small Planet level like Cross said. Oh yeah I forgot that the character capable of destroying that area was all the land on Luna which is a habitable moon around the size of our moon so in order for Skelebur is destroy all the land his blast would cover the entire surface (The top and the bottom is stretched out because it's a world  map. Also Skelebur powers himself up with nuclear energy so would that make any difference?