User blog:GreyFang82/Energy Needed to Atomize The Eiffel Tower

This is more for personal use rather than anything else...

Not only will I calculate the need energy to atomize The Eiffel Tower but I'll also calculate how much energy is needed to fragment it, violently fragment it, and pulverize it.

So first we need to know the weight of the thing... According to this website


 * http://wordpress.mrreid.org/2011/02/11/an-interesting-fact-about-the-eiffel-tower/

It weighs 7300 tons

Now thanks to this we can use the formula Mass = Volume x Density or in this case Volume = Mass / Density

So first we find the density of iron which by searching it up is 7.874 g/cm^3

Next what we do is take the 7300 tons and convert it into grams which is about 6,622,400,000 grams

Now it's 6,622,400,000 g / 7.874 g/cm^3 = 841,046,482.093 cm^3

We have the volume now!

Now we just plug in values for iron from the Vs Wiki

We will start with the less impressive feats and the work our way up

-Fragmentation-

20 j/cc

841,046,482.093 x 20 = 16,820,929,641.9 joules or 4.02 Tons of TNT => Large Building Level

-Violent Fragmentation-

42.43 j/cc

841,046,482.093 x 42.43 = 35,685,602,235.2 joules or 8.53 Tons of TNT => Large Building Level

-Pulverization-

90 j/cc

841,046,482.093 x 90 = 75,694,183,388.4 joules or 18.09 Tons of TNT => City Block Level

-Atomization-

58401 j/cc

841,046,482.093 x 58,401 = 49,117,956,000,000 joules or 11.74 Kilotons of TNT => Town Level