User blog:GreyFang82/Valev gets yeeted through a Brick Wall

Ok, so here's the info we have.

"Around 6 feet tall at the time, and considering a bit of the area around him was destroyed, i’d say 7 feet of it was destroyed, and around 4-5 feet wide was destroyed, oval-ish shape."

So the best course of action is to use the formula for a cylinder here, I'll just take the average difference between the two and try to equally distribute it by both width and height. 7 + 4.5 = 11.5 / 2 = 5.75 feet is the diameter.

5.75 / 2 =  2.875 ft = 87.63 cm is the radius.

Cccording to this website the standard brick is is 3 and 5/8th of an inch in thickness. Which is 9.2075 cm

Which is Pi x Radius ^ 2 x height.

Pi x (87.63 x 87.63) x 9.2075 = 222124.888908 cm^3

Now we plug in the values for frag of concrete.

We get 222124.888908 x 6 = 1,332,749.33 joules